How many moles of ethylene (c2h4) can react with 12.9 liters of oxygen gas at 1.2 atmospheres and 297 kelvin?
c2h4(g) + 3o2(g) yields 2co2(g) + 2h2o(g)

The moles of ethylene gas that can react is 0.212 moles

Explanation:

To calculate the moles of oxygen gas, we use the equation given by ideal gas which follows:

where,

P = pressure of the gas = 1.2 atm  

V = Volume of the gas = 12.9 L

T = Temperature of the gas = 297 K

R = Gas constant =

n = number of moles of hydrogen gas = ?

Putting values in above equation, we get:

For the given chemical equation:

By Stoichiometry of the reaction:

3 moles of oxygen gas reacts with 1 mole of ethylene gas

So, 0.635 moles of oxygen gas will react with = of ethylene gas

Hence, the moles of ethylene gas that can react is 0.212 moles