A plastic bag has a volume of 22.3 liters at a pressure of 100.0 kPa. If the pressure of the balloon is decreased at 83.5kPa, what will be the new volume of the balloon?

26.7 litres

Explanation:

Given that,

Original pressure of balloon (P1) = 100.0 kPa

Original volume of balloon (V1) = 22.3 liters

New pressure of balloon (P2) = 83.5 kPa

New volume of balloon (V2) = ?

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P2V2

100 kPa x 22.3L = 83.5 kPa x V2

2230 kPa•L = 83.5 kPa•V2

Divide both sides by 83.5 kPa

2230 kPa•L/83.5 kPa = 83.5 kPa•V2/ 83.5 kPa

26.7 L = V2

Thus, the new volume of the balloon is 26.7 litres

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

u i forgot the answer?