A 5.00 mL aliquot of a 0.20 M HCl solution is diluted to a final volume of 25.00 mL. What is the molarity of this first dilution solution? Then a second dilution was made by taking 2.00 mL of the first dilution and diluting it to 50.00 mL. g What is the molarity of this second dilution?

 The molarity of this second dilution is

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

where,

= molarity of stock  solution = 0.20 M

= volume of stock  solution = 5.00 ml

= molarity of dilute  solution = ?

=  volume of dilute solution = 25.00 ml

The molarity of this first dilution solution is 0.04 M

where,

= molarity of stock  solution = 0.04 M

= volume of stock  solution = 2.00 ml

= molarity of dilute  solution = ?

=  volume of dilute solution = 50.00 ml

The molarity of this second dilution is

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-