H3C6H507(aq) + 3NaHCO3(aq) - Na3C6H5O7(aq) + 3C02(g) + 3__

Which product formula correctly completes the equation?

1 COH2

2 H₂O

3 NaOH

4 CooH

The missing compound is H2O

Explanation:

Step 1: Data given

H3C6H507(aq) + 3NaHCO3(aq) → Na3C6H5O7(aq) + 3C02(g) + 3

The reactants are : H3C6H507(aq) + 3NaHCO3(aq)

The products are: Na3C6H5O7(aq) + 3C02(g) and

Step 2:

The reactants have 11 H atoms (8 in H3C6H5O7(aq) and 3 in NaHCO3(aq))

The products have 5H atoms (in Na3C6H5O7(aq))

Here we miss 6 H atoms

The reactants have 3 Na atoms (in 3NaHCO3(aq))

The products have 3 Na atoms (in Na3C6H5O7(aq))

The amount of Na atoms on both sides is balanced. This means the missing compound is not NaOH

The reactants have 16 O atoms (7 in H3C6H507(aq) and 9 in 3NaHCO3(aq))

The products have 13 O atoms (7 in  Na3C6H5O7(aq) and 6 in 3C02(g))

Here we miss 3 O atoms

The reactants have 9 C atoms (6 in H3C6H507(aq) and 3 in 3NaHCO3(aq))

The products have 9 C atoms (6 in Na3C6H5O7(aq) and 3 in 3CO2(g))

The amount of C is balanced on both sides.

This means the missing compound will not have a C atom.

Option 1 (COH2) and option 4 (COOH) are not possible

The missing compound is H2O