The temperature of a sample gas in a steel tank 30.00 kpa increased from 10.0 c to 25.0c what is the final pressure inside the tank?

31.59 kpa

Explanation:

The variables in this problem are temperature and pressure. Both variables are related by the gay lusaacs law.

Gay-Lussac's Law: The Pressure Temperature Law. This law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. This means that as the pressure increases so does the temperature.

From the law, we have;

P1/P2 = T1/T2

From the problem;

P1 = Intial pressure = 30 kpa

P2 = Final pressure = x

T1 = Initial temperature = 10 + 273 = 283K (Upon converting to kelvin temperature)

T2 = Final temperature = 25 + 273 = 298K (Upon converting to kelvin temperature)

Substituting into the equation, we have;

30 / P2 = 283 / 298

Upon cross multiplication, we have;

P2 = (298 * 30 ) / 283

P2 = 31.59 kpa

the answer is d. 74.02

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2