An 11 M solution containing 449.4 g of ammonium sulfate would contain how many liters?

Answer : The volume of solution will be, 0.309 L

Explanation : Given,

Mass of = 449.4 g

Molar mass of = 132 g/mole

Concentration = 11 M

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

Now put all the given values in this formula, we get:

Therefore, the volume of solution will be, 0.309 L

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