A sample of argon has a volume of 0.165L at -34.0°C and a 0.98atm of pressure. What would the volume of this gas at STP be?

0.185 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 0.98 atm

= final pressure of gas = 1 atm  (at STP)

= initial volume of gas = 0.165 L

= final volume of gas = ?

= initial temperature of gas =

= final temperature of gas =  (at STP)

Now put all the given values in the above equation, we get:

Thus the volume of this gas at STP be 0.185 L

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