According to the following reaction, what amount of Al2S3 remains when 20.00 g of Al2S3 and 2.00 g of H2O are reacted? A few of the molar masses are as follows: Al2S3 = 150.17 g/mol, H2O = 18.02 g/mol. Al2S3(s) + 6 H2O(l) ? 2 Al(OH)3(s) + 3 H2S(g)a)14.00 gb)8.33 gc)19.78 gd)17.22 ge)28.33 g