Chemistry, 17.04.2020 01:26 cheesy2271
Consider the following information. The lattice energy of KCl is Δ H lattice = − 701 kJ/mol. The enthalpy of sublimation of K is Δ H sub = 89.0 kJ/mol. The first ionization energy of K is IE 1 = 419 kJ/mol. The electron affinity of Cl is Δ H EA = − 349 kJ/mol. The bond energy of Cl 2 is BE = 243 kJ/mol. Determine the enthalpy of formation, Δ H f , for KCl ( s ) . Δ H f = kJ/mol
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Consider the following information. The lattice energy of KCl is Δ H lattice = − 701 kJ/mol. The ent...
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