Chemistry, 17.04.2020 01:45 lovelyheart5337
A 50.0 mL sample containing Cd 2 + and Mn 2 + was treated with 58.6 mL of 0.0400 M EDTA . Titration of the excess unreacted EDTA required 13.0 mL of 0.0280 M Ca 2 + . The Cd 2 + was displaced from EDTA by the addition of an excess of CN β . Titration of the newly freed EDTA required 28.6 mL of 0.0280 M Ca 2 + . What are the concentrations of Cd 2 + and Mn 2 + in the original solution
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Chemistry, 22.06.2019 18:10
Given the following at 25c calculate delta hf for hcn (g) at 25c. 2nh3 (g) +3o2 (g) + 2ch4 (g) > 2hcn (g) + 6h2o (g) delta h rxn= -870.8 kj. delta hf=-80.3 kj/mol for nh3 (g), -74.6 kj/mol for ch4, and -241.8 kj/mol for h2o (g)
Answers: 1
Chemistry, 22.06.2019 20:00
Iam hoping to create 5.72 grams of glucose. the plant was given 4.75 liters of co2 and 2.81 g of h20. which reactant was the limiting reagent? how much excess mass did we have of the other reactant?
Answers: 1
A 50.0 mL sample containing Cd 2 + and Mn 2 + was treated with 58.6 mL of 0.0400 M EDTA . Titration...
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