7. At what temperature would 343.01 g of P2O3 gas occupy 67.5 L if the pressure is 115 kPa?

26.1°C

Explanation:

T = PV / nR = (115 kPa) x (67.5 L) / ((343.01 g P2O3 / (109.94572 g P2O3/mol)) x (8.3144626 L kPa/K mol)) = 299.3 K = 26.1°C

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air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

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