How much heat is needed to increase the temperature of a 38g sample of lead from 38 C to 52 c?

121.6J

Explanation:

Given parameters:

Mass of lead  = 38g

Initial temperature = 38°C

Final temperature  = 52°C

Unknown:

Amount of heat required = ?

Solution:

The amount of heat absorbed by a substance to cause a temperature change is dependent on the mass and specific heat capacity of the body. Specific heat capacity is the amount of heat needed to cause a unit temperature rise of a mass of a substance.

mathematically, heat gained;

        H    =  m  C Ф

                 m is the mass of the lead

                  Ф is the temperature change

                  C is the specific heat capacity

Specific heat capacity of lead is 0.16J/g°C

  Insert the parameters;

           H  = 38 x 0.16 x (52-38)  = 121.6J

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