How many moles of KBr will be produced from 7 moles of BaBry?
BaBr2+ K2SO4 → KBr +BaSO4

The moles of KBr formed has been 14 mol.

The balanced chemical equation for the reaction has been:

From the balanced chemical equation, the coefficient has been describing the moles of reactants and products formed.

The balanced chemical equation has been given as:

The moles of KBr formed by 7 moles of Barium bromide has been as:

The moles of KBr formed has been 14 mol.

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7 moles of BaBr₂ produces 14 moles of KBr.

Explanation:

Given reaction is

BaBr₂ + K₂SO₄ → KBr + BaSO₄

It can be balanced by putting 2 in front of KBr as,

BaBr₂ + K₂SO₄ → 2 KBr + BaSO₄

From the above balanced equation, it was found that, 1 mole of Barium bromide required to produce 2 moles of KBr.

Now the molar ratio of BaBr₂ to KBr is written as 1 : 2.

In the same way, the molar ratio for 7 moles of BaBr₂, can be written as 7:14.

So 7 moles of BaBr₂ produces 14 moles of KBr.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3