Calculate the value of the equilibrium constant (K) at 25 °C for the reaction
2 NOBr(g) = N2(g) + O2(g) + Br2()
given that the standard free energy of formation (AG°f) of NOBr(g) is 82.4 kJ/mol

Explanation:

The equilibrium constant, Ke, at certain temperature, T, and the standard free energy of formation (ΔG°f) are related by  the equation:

From which you can obtain:

Substituting ΔG°f = 82.4kJ/mol, T = 25 + 273.15 K = 298.15 K and R = 0.008314 kJ·mol⁻¹ K⁻¹:

Rounding to three significant figures:

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.

a) the particles of the chair are strongly held together.