Aluminum Oxide is formed when aluminum combines with oxygen in the air. How many grams of Al2O3 are formed when 23.6g of Al reacts completely with oxygen?
4 Al + 3 O2 —> 2 Al2O3
A. 44.6 grams B. 35.6 grams C. 87.6 grams D. 21.6 grams

Taking into account the reaction stoichiometry, the correct answer is option A. 44.6 grams.

In first place, the balanced reaction is:

4 Al + 3 O₂  → 2 Al₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Al: 4 moles O₂: 3 moles  Al₂O₃: 2 moles

The molar mass of the compounds is:

Al: 27 g/mole O₂: 32 g/mole  Al₂O₃: 102 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Al: 4 moles× 27 g/mole= 108 gramsO₂: 3 moles× 32 g/mole= 96 grams  Al₂O₃: 2 moles× 102 g/mole= 204 grams

Then the following rule of three can be applied: if by reaction stoichiometry 108 grams of Al form 204 grams of Al₂O₃, 23.6 grams of Al form how much mass of Al₂O₃?

mass of Al₂O₃= 44.6 grams

Then, 44.6 grams of Al₂O₃ are formed when 23.6 g of Al reacts completely with oxygen.

Finally, the correct answer is option A. 44.6 grams.

Learn more:

linklinklink

The correct answer to the question is Option A. 44.6 g

The balanced equation for the reaction is given below:

4Al + 3O₂ —> 2Al₂O₃

Next, we shall determine the mass of Al that reacted and the mass of Al₂O₃ produced from the balanced equation.

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 4 × 27 = 108 g

Molar mass of Al₂O₃ = (27×2) + (3×16)

= 54 + 48

= 102 g/mol

Mass of Al₂O₃ from the balanced equation = 2 × 102 = 204 g

SUMMARY:

From the balanced equation above,

108 g of Al reacted to produce 204 g of Al₂O₃.

Finally, we shall determine the mass of Al₂O₃ produced by the reaction of 23.6 g of Al. This can be obtained as follow:

From the balanced equation above,

108 g of Al reacted to produce 204 g of Al₂O₃.

Therefore,

23.6 g of Al will react to produce = = 44.6 g of Al₂O₃

Thus, 44.6 g of Al₂O₃ were obtained from the reaction.

Hence, Option A. 44.6 g gives the correct answer to the question.

Lean more: link

I’m pretty sure it’s false i’m not sure

If a hydrogen atom is neutral, it must also have  one electron. an oxygen atom (o) has an atomic number of eight (8). this means a neutral oxygen atom has eight protons and eight electrons. the element actium (ac) has an atomic number of 89, so it has 89 protons and 89 electrons in a neutral atom