Please consider the following gas phase reaction and its experimentally determined rate law expression. If the concentration of A is tripled and the concentration of B is doubled, the reaction rate would be increased by a factor of:.
A + B → C rate = k[A]^2 [B]
A) 6
B) 9
C) 12
D) 18
E) 36

D) 18

Explanation:

Hello,

In this case, by considering the given rate law:

We also take into account that the concentration of A is tripled and the concentration of B is doubled, therefore, we have:

Which results in an increasing factor of:

By considering only the tripling and the doubling, thus, the answer is D) 18.

Regards.

i would say b

explanation:

but i think i would need more information than that