To whomever gets this right i will give 68 points on the next question for them and the brainliest answer. NEED HELP!
Lithium's atomic number is 3. Fluorine's is 9. Explain how an atom of lithium and an atom of fluorine combine by ionic bonding.

The answer to your question is below

Explanation:

The information given is not important to determine if the bond is ionic.

An ionic bond is when a metal and a nonmetal combine or when the electronegativity of the elements is higher than 1.7.

In this example, lithium is a metal and fluorine is a nonmetal so they will form an ionic compound.

Lithium is in group lA so it has 1 electron in its outermost shell.

Fluorine is in group VIIA so it has 7 electrons in its outermost shell.

Lithium donates one electron to fluorine so they become stable.

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years