At what temperature will a balloon have a volume of 6.08 L if the temperature is 41.0 ℃ when its volume is 4.87 L? Answer in Kelvin.
P. S please show the equation steps.

392.20K

Explanation:

-We apply Charles' Law which states that for an ideal gas at constant pressure, its volume is directly proportional to it's temperature:

-Given that:

#We substitute in the ratio formula above and calculate for :

Hence, the temperature of the balloon at a volume of 6.08L is 392.20K

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

one state would change   like louisiana to texas. thats a change

explanation: