Hydrogen peroxide decomposes spontaneously to yield water and oxygen gas according to the reaction equation 2h2o2(aq)⟶2h2o(l)+o2(g) the activation energy for this reaction is 75 kj·mol−1. the enzyme catalase, found in blood, lowers the activation energy to 8.0 kj·mol−1. at what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25 °c?

the temperature of the non- catalyzed reaction is = 2793.75 K

Explanation:

The reaction of the spontaneous decomposition of hydrogen peroxide to give water and oxygen is given as:

The activation energy of non-catalyzed reaction

The activation energy of metal catalyzed reaction

The temperature of metal catalyzed reaction = (25+273)K = 298 K

The rate constant of the non-catalyzed reaction can be expressed as:

----- equation (1)

The rate constant of the metal catalyzed reaction can be expressed as:

Then

Thus; the temperature of the non- catalyzed reaction is = 2793.75 K

did anyone actually do this? like if anyone has submitted this i rly need .