Consider the following cyclic process carried out in two steps on a gas.
Step 1: 35 J of heat is added to the gas, and 12 J of expansion work is performed.
Step 2: 65 J of heat is removed from the gas as the gas is compressed back to the initial state.
Calculate the work for the gas compression in Step 2. J

The work for the gas compression is 42 J

Explanation:

Step 1: Data given

35 J of heat is added to the gas

12 J of expansion work

65 J of heat is removed from the gas as the gas is compressed back to the initial state

Step 2:

ΔE = q + w

⇒with q = 35 J of heat

⇒with w = 12 J of expansion work

  ⇒ expansion work = work done by the gas = w is negative

ΔE = 35 J - 12 J

ΔE = 23 J

Step 3: Calculate the work for the gas compression

ΔE = -23 J = -65 J + w

⇒65 J of heat is removed from the gas as the gas is compressed back to the initial state

⇒ We need 23 J to go back to the initial state: ΔE = -23 J

Compressed gas means work done by the surroundings => w is positive

w = -23 J + 65 J = 42 J

The work for the gas compression is 42 J

58750.08068 is the answer i think

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.