Group 1 cations precipitate easily in a relatively high concentration of hydrochloric acid. After the separation from the other group 1 cations, the presence of lead can be tested by addition of potassium chromate. Explain what is wrong with the given equation for this test. Pb(aq) + CrO4(aq) <-> PbCrO(aq)

The oxidation of the lead is not indicated, also the charge on Chromate,

Explanation:

The lead in the aqueous form is +2 and the charge of Chromate is -2 i.e CrO4^-2, and also the product should be PbCrO4

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.