Calculate enthalpy changes for the following: 0.047 g of sulfur (rhombic) burns, forming ( for = – 296.84 kJ/mol) Enthalpy change = kJ 0.22 mol of decomposes to and ( for = –90.83 kJ/mol) Enthalpy change = kJ 2.44 g of is formed from and excess ( for = –45.90 kJ/mol) Enthalpy change = kJ mol of carbon is oxidized to ( for = –393.509 kJ/mol) Enthalpy change = kJ

Complete Question

Calculate enthalpy changes for the following:

a

0.047 g of sulfur (rhombic)  burns, forming  ( for    = – 296.84 kJ/mol)

Enthalpy change =______________ kJ

b

0.22 mol of decomposes to and and   ( for = –90.83

kJ/mol) Enthalpy change = ______________kJ

c

2.44 g of    is formed from and excess and excess (

for = –45.90 kJ/mol)

Enthalpy change =___________________ kJ

d

mol of carbon is oxidized to   (  for = –393.509 kJ/mol)

 Enthalpy change =__________________ kJ

a

b

c

d

Explanation:

For a

    The number o moles () =

The Change in enthapy  is mathematically represented as

    Substituting values

For b

   The Change in enthapy  is mathematically represented as

      Substituting values

For  c

   The number o moles () =

The Change in enthapy  is mathematically represented as

    Substituting values

For d

         The Change in enthapy  is mathematically represented as

      Substituting values