What is the reaction corresponding to the standard enthalpy of formation of K2SO3(s)?

Explanation:

The standard enthalpy of formation of a substance is the change in enthalpy that happens when one mole of the substance is formed from the elements in their standard states.

Thus, to calculate the standard state of formation of a compound you must:

Applying that to our compound K₂SO₃

1. Elements:

2. Standard forms of the elements:

3. Reaction:

Balance, keeping one mole of  K₂SO₃. You will need to use fractional coefficients for some elements:

cc jyfu65   6r 67r   r576dyfu r6tyuio fghjkl;

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.