A gas occupies 4.31 liters at a pressure of 101.325 kPa. Determine the new volume at 80.8 kPa.

v2= 5.404L

Explanation:

using Boyle's law

p1 x v1 = p2 x v2

101.325 x 4.31 = 80.8 x v2

v2= (101.325 x 4.31)\80.8

v2= 5.404L

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it

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