Calculate the temperature of a gas that originally occupied 3.45 L and is expanded to 5.25 L. The original temperature of the gas was 282K and the pressure remains constant

156 °C  

Explanation:

This looks like a case where we can use Charles’ Law:  

Data:

V₁  = 3.45 L; T₁ = 282 K

V₂ = 5.25 L; T₂ = ?  

Calculation:

(c) Convert the temperature to Celsius

T₂ = (429 – 273.15) °C = 156 °C

describe matter a earth

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