How many grams of caf2 are present in 1.25 l of a 0.15 m solution of caf2

9.36g of CaF2 is presnt in the solution.

Explanation:

CaF2 molar concentration is 0.15mol in 1.25l of solution.

1. Convert this to the standard concentration in mol/dm3:

1dm3 = 1 L

0.15mol = 1.25 dm3

x =1 dm3

0.15 = 1.25 x

x = 0.15/1.25

x = 0.12 mol/dm3

2. Calculate the relative molecular mass of CaF2

Ca= 40, F =19

RMM = 40 + 19 *2

RMM = 40+ 38

RMM = 78g/mol

3. Calculate the concentration in g/dm3

conc. in mol/dm3 = conc in g/dm3 / RMM

conc in g/dm3 = conc in mol/dm3 * RMM

= 0.12mol/dm3 * 78g/mol

= 9.36 g/dm3

So therefore, 9.36g of CaF2 is presnt in the solution.