At STP between 4.0 g of helium and 44.0 g of carbon dioxide

Borne helium and carbon dioxide will have the same number of molecules

Helium will have more molecules than carbon dioxide

Carbon dioxide will have more molecules than helium

Insufficient data

Both helium and carbon dioxide will have the same number of molecules

Explanation:

Step 1:

Data obtained from the question.

Mass of He = 4g

Mass of CO2 = 44g

Step 2:

Determination of the number of mole of He and CO2. This is illustrated below:

For He:

Molar Mass of He = 4g/mol

Mass of He = 4g

Number of mole = Mass/Molar Mass

Number of mole of He = 4/4

Number of mole of He = 1 mole

For CO2 :

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 = 44g

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 44/44

Number of mole of CO2 = 1 mole

Step 3:

Determination of the number of molecules.

From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules.

This means that 1 mole of He will contain 6.02x10^23 molecules and 1 mole of CO2 will also contain 6.02x10^23 molecules.

Therefore, both 4g of He and 44g of CO2 contains the same number of molecules i.e 6.02x10^23 molecules