A saturated solution of KClO3 is dissolved in 100 mL of water. If the saturated solution is cooled from 90oC to 60oC, how many grams of precipitate will be formed?

24 g

Explanation:

To find the mass of precipitate that will be formed we need to use the solubility curve of KClO₃ in the water. From that graphic of solubility curve of KClO₃ in water, we have that:  

The mass of the saturated solution of KClO₃ in 100 mL of water at 90 °C is = 50 g

The mass of the saturated solution of KClO₃ in 100 mL of water at 60 °C is = 26 g

Hence, by the difference of the mass of KClO₃ between 90 °C and 60 °C we can find the grams of precipitate that will be formed:

Therefore, 24 g of KClO₃ precipitate will be formed.

I hope it helps you!  

plants need sunlight, water, and carbon dioxide to make food. plants use the raw materials of water, nutrients they absorb from soil, and carbon dioxide to make sugars the plant can use. energy from the sun and chlorophyll are also needed.

explanation:

a