If 45.0 g of C6H12O6, are dissolved in 215 g of H2O, what will be the boiling point of the resulting solution?

(Kb= 0.52oC/m)

A) 100.00oC
B) 100.22oC
C) 100.60oC
D) 112.35oC

C. 100.60oC

Explanation:

Find the molality of the solution first, 1.16 m. Then, multiply by the Kb of 0.52. Then, add that number to the boiling point of pure water (100o). This is the new boiling point of the solution 100.60o.

6.4 cm (max) - 25 cm (min)

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.