How much volume is needed, if given 92.0 L of Hydrogen gas in a container of 612 kPa and reduces to 228kPa

246.94 litres is the volume is needed, if given 92.0 L of Hydrogen gas in a container of 612 kPa and reduces to 228kPa.

Explanation:

Data given:

Initial volume of hydrogen gas in the container P1 = 92 litres

initial pressure of hydrogen gas in the container  V1 = 612 kPa

final pressure of hydrogen gas on the container P2= 228kPa

final volume of hydrogen gas on the container V2 =?

from the data we will require equation of Boyle's law to calculate the unknown volume:

P1V1 = P2V2

V2 =

putting the values in the equation:

V2 =

V2 = 246.94 Litres.

246.94 litres will be the volume of the hydrogen gas when pressure geta reduced to 228 kPa.

um i think it might be a car?