What volume of 3.00 M CH3COOH solution is needed to provide 0.220 mol of CH3COOH?

The volume of the 3.00 M CH₃COOH solution needed to provide 0.220 mol of CH₃COOH is 73.33 mL

From the question,

We are to determine the volume of the 3.00 M CH₃COOH solution is needed to provide 0.220 mol of CH₃COOH

From the formula

Number of moles = Concentration × Volume

Then, we can write that

From the given information

Number of moles = 0.220 mol

Concentration = 3.00 M

Putting the parameters into the formula, we get

Volume = 0.07333 L

Volume = 73.33 mL

Hence, the volume of the 3.00 M CH₃COOH solution needed to provide 0.220 mol of CH₃COOH is 73.33 mL

Learn more here: link

0.0733L of 3.00 M CH3COOH solution is needed to provide 0.220 mol of CH3COOH.

Explanation:

Molarity, M = moles of the molecule / Liter of solution

Therefore, we can work backwards to find the number of litres of solution, if we are given the number of moles

The values are a given as,

The molarity of the solution =3.00M

The final moles = 0.220 moles.

 0.220 mol CH3COOH ( 1L / 3.00 mol CH3COOH) = 0.220/3.00                          

                                                                                     =0.0733L of solution

58 km per hour : d

the answer is true. hope it .