When 200. milliliters of an HNO3 solution is exactly neutralized by 250 milliliters of a 0.50 M solution of KOH, what is the concentration of HNO3

Molarity HNO₃ Soln = 0.625M

Explanation:

Molarity of Acid Soln X Volume Acid Soln = Molarity of Base Soln x Volume of Base Soln

Molarity HNO₃ Soln x 200-ml HNO₃ Soln = 0.50M KOH Soln x 250-ml KOH Soln

Molarity HNO₃ Soln = (0.50M)(250ml)/(200ml) = 0.625M

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8

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