Hey! Please help,

Ice melts into water. the correct equation to calculate the heat of this reaction is...

q=mCΔT

q=mΔHv

q=mΔHf

q=mc^2

Thank you :)

A

Explanation:

When finding how much heat is released in specific heat problems, we use the formula

When calculating for the amount of Joules applied or lost, we change the original equation of

To

Specific heat calculations can sometimes get tricky with the formulas, but once the first part of learning how to change the equation is down, everything is a breeze from there!

I'm happy to help with any other questions you might have in the future and I will do my best to provide the brainliest answers :)

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g