What is the mole ratio between ammonium sulfate (NH4)2SO4 and ammonia (NH3) ?

the mole ratio of ammonium sulfate to ammonia is 1:2. Hence, our sample of 30.0 moles of ammonia will produce:

1

2

×

30.0

m

o

l

=

15.0

m

o

l

of ammonium sulfate.

the answer is c. nacl

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2