What is the new pressure acting on a 2.5 l balloon if its original volume was 5.8 l at 3.7 ATM of pressure?

The new pressure is 8.58 atm

Explanation:

Using Boyle's law which states that the pressure of a gas is inversely proportional to the volume of the gas and mathematically written as;

         P1 V1 = P2 V2

P1 = 3.7atm

V1 = 5.8L

V2 = 2.5L

P2 = ?

Equate the values to the equation and solve for P2:

P2 = P1 V1 / V2

P2 = 3.7 * 5.8 / 2.5

P2 = 21.46 / 2.5

P2 = 8.584 atm

The new pressure acting on the balloon is therefore 8.58atm

"the periodic table is arranged in order of atomic number."

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.