The rate of a reaction is found to double when the concentration of one reactant is quadrupled (increased by a factor of 4). The order of the reaction with respect to this reactant is
one quarter (1/4)
First
one half (1/2)
Second

Half (1/2)

Explanation:

according to R = k[A].

when A is quadrupled and reaction order is half,it becomes.

R= k[4A]^1/2

R=k2[A]^1/2.

it aligns with the question.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.

nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.