If the pressure of a gas is 1.50 atm, its volume is 2.50 L, and its temperature is 22, what is the volume if the pressure is increased to 3.00 atm and the temperature is increased ton35

The answer to your question is V2 = 1.3 l

Explanation:

Data

Pressure 1 = P1 = 1.5 atm

Volume 1 = V1 = 2.50 l

Temperature 1 = T1 = 22°C

Pressure 2 = P2 = 3 atm

Volume 2 = V2 = ?

Temperature 2 = T2 = 35°C

Process

1.- Convert temperature to °K

T1 = 22 + 273 = 295°K

T2 = 35 + 273 = 308°K

2.- Use the combine gas law to solve this problem

                P1V1/T1 = P2V2/T2

-Solve for V2

                V2 = P1V1T2 / T1P2

3.- Substitution

                V2 = (1.5 x 2.5 x 308) / (295 x 3)

4.- Simplification

                V2 = 1155 / 885

5.- Result

                 V2 = 1.3 l