When potassium chlorate decomposes it produces potassium chloride and oxygen gas. If 223.65 g of potassium chloride was produced, how much potassium chlorate did the reaction start with?

367.7466 g of potassium chlorate is produced.

Explanation:

Given data:

223.65 g of potassium chloride is produced

Question: How much potassium chlorate did the reaction start with, mKClO₃ = ?

The balanced reaction:

2KClO₃ → 2KCl + 3O₂

Information needed:

Molecular weight of KClO₃ = 122.5 g/mol

Molecular weight of KCl = 74.5 g/mol

Molecular weight of O₂ = 32 g/mol

You can see in the reaction that 2 moles of KClO₃ gives 2 moles of KCl.

Mass of KClO₃:

Mass of KCl:

245 g KClO₃ --------- 149 g KCl

X g KClO₃ ------------- 223.65 g KCl

i need mutiple choices

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.