A helium balloon has a volume of 735 mL when it is at ground level. The balloon is
transported to an elevation of 5km, where the pressure is only 0.8atm. At this altitude the gas
occupies a volume of 1286mL. Assuming the temperature has remained the same, what was
the ground level pressure?
O
A.
1.4atm
OB. 0.7atm
O c. 12am
OD. 1.0atm

The answer to your question is P1 = 1.4 atm

Explanation:

Data

Volume 1 = V1 = 735 ml

Pressure 1 = P1 = ?

Volume 2 = V2 = 1286 ml

Pressure 2 = P2 = 0.8 atm

Process

To solve this problem use Boyle's law.

          P1V1 = P2V2

-Solve for P1

          P1 = P2V2 / V1

-Substitution

          P1 = (0.8 x 1286) / 735

-Simplification

          P1 = 1028.8 / 735

-Result

          P1 = 1.4 atm

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question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)