How many grams of MgCl2 will be produced from 12.0g of Mg(OH)2 and 42.0g of HCl

The answer to your question is 19.7 g of MgCl₂

Explanation:

Data

mass of MgCl₂ = ?

mass of Mg(OH)₂ = 12 g

mass of HCl = 42 g

Balanced chemical reaction

         Mg(OH)₂  +  2HCl   ⇒   MgCl₂   + 2H₂O

Process

1.- Calculate the molar mass of the reactants

Mg(OH)₂ = 24 + 32 + 2 = 58 g

HCl = 1 + 35.5 = 36.6 x 2 = 72 g

2.- Calculate the theoretical yield

Mg(OH)₂ / HCl = 58 / 78 = 0.74

3.- Calculate the experimental yield

Mg(OH)₂ / HCl = 12 / 42 = 0.28

4.- Dertermine which is the limiting reactant

The limiting reactant is Mg(OH)₂ because the theoretical yield was lower than the experimental yield.

5.- Calculate the mass of MgCl₂

              58 g of Mg(OH)₂ 95 g of MgCl₂

               12 g of Mg(OH)₂    x

                         x = (12 x 95)/58

                         x = 19.7 g of MgCl₂

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it

the volume increases