If 1.178 mol of pure helium gas at 2.59 atm occupies a 10.50 L canister, what 1 point
is the temperature of the gas in degrees Celsius? *

The answer to your question is T = 281.5°K

Explanation:

Data

number of moles = 1.178

pressure = 2.59 atm

volume = 10.5 l

temperature = ?

constant of ideal gases = 0.082 atm l/mol°K

Process

1.- Write the formula of ideal gases

         PV = nRT

-Solve for T

         T = PV / nR

2.- Substitution

          T = (2.59 x 10.5) / (1.178 x 0.082)

3.- Simplification

           T = 27.195 / 0.0966

4.- Result

            T = 281.5°K

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