A student needs to dilute a 0.31 M Pb(NO3)2 solution to make 83.0 mL of 0.19 M Pb(NO3)2 . Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.31 M Pb(NO3)2 solution that is needed.

Answer : The volume, in milliliters, of the 0.31 M solution that needed is, 50.9 mL

Explanation :

Formula used :

where,

are the initial molarity and volume of dilute .

are the final molarity and volume of .

We are given:

Putting values in above equation, we get:

Hence, the volume, in milliliters, of the 0.31 M solution that needed is, 50.9 mL

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