A sample of gas in a closed container at a
temperature of 72°C and a pressure of 5 atm
is heated to 284°C. What pressure does the
gas exert at the higher temperature?
Answer in units of atm.

8.07 atm

Explanation:

Use Gay-Lussac's law and rearrange forumula

Change C to K

- Hope that helps! Please let me know if you need further explanation.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :