How much heat is released when 0.762 mol of copper cools from 81.6°C to 52.2°C?

550 J

Explanation:

The formula for the amount of heat (q) released by the copper is

q = mCΔT

Data:

  n = 0.762 mol

  C = 0.386 J°C⁻¹g⁻¹

T_i = 81.6 °C

T_f = 52.2 °C  

Calculations:

(a) Mass of copper

\text{Mass} = \text{0.762 mol} \times \dfrac{\text{63.55 g}}{\text{1 mol}} = \text{48.43 g}

(b) ΔT

ΔT = 81.6 °C - 52.2 °C = 29.4 °C

(c) q

q = mCΔT = 48.43 g × 0.386 J·°C⁻¹g⁻¹ × 29.4 °C = 550 J

The amount of heat released by the copper is 550 J.

the answer is a and have a great day