How many grams of sodium chloride are required to make a 1.0 l solution with a concentration of 3.5 m?

204.75 grams of sodium chloride are required.

Explanation:

n = moles of compound

V = volume of the solution in liters.

We have :

Molarity of the solution = 3.5 M

Volume of the solution = 1.0 L

Moles of sodium chloride = n

n = 3.5 M × 1.0 L = 3.5 mol

Mass of 3.5 moles of sodium chloride : 3.5 mol × 58.5 g/mol = 204.75 g

204.75 grams of sodium chloride are required.

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