How many grams of nitrogen will be produced in a reaction between ammonia and dinitrogen monoxide in which the total heat energy released was 505 KJ?
2 NH3 + 3 N2O = 4 N2 + 3 H2O DELTA Hrxn= ?
Given:
4 NH3 + 3 O2 = 2 N2 + 6 H2O DELTA Hrxn= -1556KJ
N2O + H2 = N2 + H2O DELTA Hrxn= -389.4 KJ
H2+ ½ O2 = H2O DELTA Hrxn= -223.9 KJ
Answers: 2
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