Outline a mechanism for the dehydration of 4-methylcyclohexanol catalyzed by phosphoric acid

Dehydration of 4-methylcyclohexanol
Here are the steps for the dehydration of 4-methylcyclohexanol:

The OH group is protonated. 
OH2 evaporates as a water molecule 
Only carbocation  left over. 
At last,
A proton leaves and the double bond comes into existence.
See the diagram in the attachment.

Detailed mechanism has been shown below.

Explanation:

4-methylcyclohexanol is a secondary alcohol. We know that secondary and tertiary alcohol undergoes dehydration through E1 elimination pathway in presence of an acid catalyst.

Here 4-methylcyclohexanol gets protonated first. Then one molecule leaves to form a carbocation. After that deprotonation takes place by to form an alkene.

Here the product forms due to dehydration is - 4-methylcyclohexene.

detailed mechanism has been shown below.

Ibelieve the answer is d

The velocity would be 2