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Chemistry, 05.05.2020 23:02 vipergod07
You have the equations:
2H2O(l)→2H2(g)+O2(g), △H=572 kJ
2N2(g)+3H2(g)→2NH3(g), △H=−138 kJ
2NO2(g)+7H2(g)→2NH3(g)+4H2O(l), △H=−1.18×103 kJ 2NO2(g)→2N2(g)+2O2(g), △H=□
What is the missing △H ?
−1.38×103 kJ
+99.0 kJ
+1.38 × 10³ kJ
−138 kJ
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Answers: 3
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You know the right answer?
You have the equations:
2H2O(l)→2H2(g)+O2(g), △H=572 kJ
2N2(g)+3H2(g)→2NH3(g...
2H2O(l)→2H2(g)+O2(g), △H=572 kJ
2N2(g)+3H2(g)→2NH3(g...
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