How much heat(energy) would be required to raise 20 grams of an unknown substance from 23 degrees Celsius to 33 degrees Celsius

q = 836 J  

Explanation:

The amount of heat required to raise 20 grams of an unknown substance from 23° Celsius to 33° Celsius can be computed below

The specific heat capacity of the substance is not given, so let us assume the specific heat capacity of the substance is 4.18J/g°C.

q = mcΔt

where

q = amount of heat energy

m = mass

c = specific heat capacity

Δt = change in temperature

Δt = 33°C - 23°C = 10°C

q = mcΔt

q = 20 g × 4.18 J/g°C × 10° C

g cancel g and °C cancels °C . We are left with joules

q = 836  J  

the dissolution of polymer can be thermodynamically described in 2 steps.