How much energy would be absorbed as heat by 75 g of iron when heated from 295 k to 301 k?

q = 202.5 joules

Explanation:

The amount of energy absorbed as one heat 75 grams of iron from 295 k to 301 k can be computed below

q = mcΔt

where

q = energy

m = mass

c = specific heat capacity

Δt = change in temperature

Δt = final temperature - initial temperature

Δt = 301 - 295 = 6 k

c = 0.45  J/g  K

q =  75 g × 0.45 J/g  K × 6 K

g cancels g and k cancels k we are left with the unit in joules

q = 202.5 joules

hurricanes form when warm, moist air from the ocean surface quickly rises into the atmosphere and forms storm clouds and rain. when the clouds are formed, heat is released which warms the cool air in the upper regions of the atmosphere so that the cycle can continue. which two phases of the water cycle are repeated in this process?